DokuWiki - fricklers.org

Trace:

Differences

This shows you the differences between two versions of the page.

Link to this comparison view

Both sides previous revisionPrevious revision
Next revision
Previous revision
Last revisionBoth sides next revision
streetmath [2020/03/08 12:00] mariostreetmath [2020/03/08 17:19] mario
Line 3: Line 3:
 Questions: Questions:
   - Given the speed difference between $C$ and $B$ and the total speed of $B$, what time $T$ does it take for $C$ to overtake $B$?    - Given the speed difference between $C$ and $B$ and the total speed of $B$, what time $T$ does it take for $C$ to overtake $B$? 
-  - And what distance $D$ do both vehicles travel while the overtake takes place?+  - What distance $D$ does the bicycle $B$ travel while the overtake takes place?
  
 === Mathematical Model === === Mathematical Model ===
Line 11: Line 11:
   * $w$:   relative window size   * $w$:   relative window size
  
 +<WRAP center round info 60%>
 For example, the driver travels at $v_C$ = 30 km/h, the cyclist at $v_B$ = 20 km/h, and the relative window size is $w$ = 10 m, that is $C$ switches the lane 5 m behind $B$, passes $B$, and switches the lane again when $C$ is 5 meters in front of $B$.  For example, the driver travels at $v_C$ = 30 km/h, the cyclist at $v_B$ = 20 km/h, and the relative window size is $w$ = 10 m, that is $C$ switches the lane 5 m behind $B$, passes $B$, and switches the lane again when $C$ is 5 meters in front of $B$. 
 +</WRAP>
  
 Consider the speed difference $\Delta_v = v_C - v_B$ of $C$ and $B$. Regarding question 1, take $B$ as the reference point. Then $C$ approaches $B$ with speed $\Delta_v$ and needs to travel a distance of $w$ in order to safely overtake $B$. We obtain Consider the speed difference $\Delta_v = v_C - v_B$ of $C$ and $B$. Regarding question 1, take $B$ as the reference point. Then $C$ approaches $B$ with speed $\Delta_v$ and needs to travel a distance of $w$ in order to safely overtake $B$. We obtain
 \[ T = \frac{w}{\Delta_v}.\] \[ T = \frac{w}{\Delta_v}.\]
  
-Example:+<WRAP center round info 60%> 
 +Example: It takes
 \[ T  \[ T 
 = \frac{10 \,\text{m}}{30 \frac{\,\text{km}}{\,\text{h}} - 20 \frac{\,\text{km}}{\,\text{h}}} = \frac{10 \,\text{m}}{30 \frac{\,\text{km}}{\,\text{h}} - 20 \frac{\,\text{km}}{\,\text{h}}}
Line 24: Line 27:
 = 3.6 \,\text{s} = 3.6 \,\text{s}
 \] \]
 +for $C$ to overtake $B$ if their speed difference is 10 km/h.
 +</WRAP>
 +
 +Now, using $T$ and the reference speed $v_B$ of the cyclist, it is easy to calculate
 +\[
 +D = v_B \cdot T.
 +\]
 +
 +<WRAP center round info 60%>
 +Again, in our running example we have
 +\[
 +D = 20 \,\frac{\text{km}}{\text{h}} \cdot 3.6 \,\text{s}
 += 20 \,\frac{1000\,\text{m}}{3600\,\text{s}} \cdot 3.6 \,\text{s}
 += 20 \,\text{m}.
 +\]
 +</WRAP>
 +
 +Now it remains to add the relative window size $w$ to $D$ in order to get the distance $C$ travels from the beginning of the overtake until its end.
 +
 +<WRAP center round info 60%>
 +In total, overtaking a cyclist riding at 20 km/h while driving a car at 30 km/h takes 3.6 s and meanwhile the cyclist travels 20 m. In order to avoid hitting the cyclist, the driver needs to overview 30 m ahead.
 +</WRAP>